1. In △ABC, AB = 5 cm and BC = 6 cm. Then, the length of AC cannot be
3.4 cm
3.8 cm
3.6 cm
3.9 cm
2. In figure, ABCD is a quadrilateral in which AB = BC and AD = DC. Measure of ∠BCD is:
105°
125°
85°
100°
3. In the adjoining figure, △ABC ≅ △ADC. If ∠BAC = 30∘ and ∠ABC = 100∘ then ∠ACD is equal to
50°
80°
60°
76°
4. It is not possible to construct a triangle when the lengths of its sides are
5.3cm, 2.2cm, 3.1cm
5.8cm, 3.2cm, 3.3cm
5cm, 2.2cm, 3cm
5cm, 2cm, 5cm
5. In fig, AC = BC and ∠ACY = 140∘. Find X and Y:
110° and 110°
180° and 110°
120° and 190°
50° and 70°
6. In △ABC and △DEF, AB = DE and ∠A = ∠D.Then two triangles will be congruent by SA axiom if:
BC = DE
AC = EF
AC = DE
none of these
7. D is a Point on the Side BC of a △ABC such that AD bisects ∠BAC then:
CD = CA
CD > CA
BA > BD
BD = CD
8. In the adjoining figure, O is Mid – point of AB. If ∠ACO = ∠BDO, then ∠OAC is equal to
∠OBD
∠ODB
∠DBO
∠OCA
9. In the adjoining fig, AD = BC and ∠BAD = ∠ABC. If ∠BAD = 120∘ and ∠ABD = 35∘, then ∠CAD is
80°
105°
85°
25°
Class 9 Triangles Quiz -2Time limit: 0
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