1. In △ABC, AB = 5 cm and BC = 6 cm. Then, the length of AC cannot be
3.4 cm
3.8 cm
3.6 cm
3.9 cm
2. In figure, ABCD is a quadrilateral in which AB = BC and AD = DC. Measure of ∠BCD is:
105°
125°
85°
100°
3. In the adjoining figure, △ABC ≅ △ADC. If ∠BAC = 30∘ and ∠ABC = 100∘ then ∠ACD is equal to
50°
80°
60°
76°
4. It is not possible to construct a triangle when the lengths of its sides are
5.3cm, 2.2cm, 3.1cm
5.8cm, 3.2cm, 3.3cm
5cm, 2.2cm, 3cm
5cm, 2cm, 5cm
5. In fig, AC = BC and ∠ACY = 140∘. Find X and Y:
110° and 110°
180° and 110°
120° and 190°
50° and 70°
6. In △ABC and △DEF, AB = DE and ∠A = ∠D.Then two triangles will be congruent by SA axiom if:
BC = DE
AC = EF
AC = DE
none of these
7. D is a Point on the Side BC of a △ABC such that AD bisects ∠BAC then:
CD = CA
CD > CA
BA > BD
BD = CD
8. In the adjoining figure, O is Mid – point of AB. If ∠ACO = ∠BDO, then ∠OAC is equal to
∠OBD
∠ODB
∠DBO
∠OCA
9. In the adjoining fig, AD = BC and ∠BAD = ∠ABC. If ∠BAD = 120∘ and ∠ABD = 35∘, then ∠CAD is
80°
105°
85°
25°
Class 9 Triangles Quiz 2Time limit: 0
Quizsummary0 of 10 questions completed Questions:
Information
Click on ‘Start Quiz’ to Take Test. You have already completed the quiz before. Hence you can not start it again. Quiz is loading... You must sign in or sign up to start the quiz. You have to finish following quiz, to start this quiz: Results0 of 10 questions answered correctly Your time: Time has elapsed You have reached 0 of 0 points, (0) Categories
