1. Find the degree of the polynomial 4x^{4} + 0x^{3} +0x^{5} + 5x+7?
a. 6
b. 4
c. 5
d. 2
2. Find the value of the polynomial 5x − 4x^{2}+3, when x = −1?
a. 6
b. 5
c. 3
d. 4
3. If p(x) = x + 3, then find p(x) + p (x)?
a. 10
b. 12
c. 6
d. 18
4. Find the zero of the polynomial p(x) = 5x – 2?
a. 12/5
b. 7/5
c. 23/5
d. 2/5
5. Find one of the zeroes of the polynomial 2x^{2} +7x – 4?
a. 1/2
b. 5
c. 9
d. 1/5
6. If x^{51}+51 is divided by x+1, then find the remainder?
a. 55
b. 45
c. 62
d. 50
7. If x+1 is a factor of the polynomial 2x^{2}+kx+1, then find the value of ‘k’?
a. 3
b. 5
c. 8
d. 12
8. Find the value of 249^{2}−248^{2}?
a. 543
b. 497
c. 235
d. 653
9. The factorization of 9x^{2}−3x−20 is
a. (3x + 4) (3x – 5)
b. (3x + 4)
c. (3x – 5)
d. (3x – 4) (3x – 5)
10. If a + b +c = 0, then find a^{3}+b^{3}+c^{3}?
a. abc
b. 2abc
c. 3abc
d. 1
Chapter  2 Polynomials Quiz1  Math Class 9th
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Question 1 of 10
1. Question
Find the degree of the polynomial 4x^{4} + 0x^{3} +0x^{5} + 5x+7?
Correct
4x^{4} + 0x^{3} +0x^{5} + 5x+7
4x^{4} + 5x + 7
Here, the highest power is 4.
Therefore, the degree of given polynomial is 4.Incorrect
4x^{4} + 0x^{3} +0x^{5} + 5x+7
4x^{4} + 5x + 7
Here, the highest power is 4.
Therefore, the degree of given polynomial is 4. 
Question 2 of 10
2. Question
Find the value of the polynomial 5x − 4x^{2}+3, when x = −1?
Correct
5x − 4x^{2}+3
−4x^{2} + 5x + 3
Putting x= 1 in the given polynomial, we get
−4 (−1)^{2}+5(−1) +3
= −4−5+3
= −9+3
= −6Incorrect
5x − 4x^{2}+3
−4x^{2} + 5x + 3
Putting x= 1 in the given polynomial, we get
−4 (−1)^{2}+5(−1) +3
= −4−5+3
= −9+3
= −6 
Question 3 of 10
3. Question
If p(x) = x + 3, then find p(x) + p (x)?
Correct
P(x) = x + 3
And p (x) = x + 3
Then, p(x) + p (x)
= x + 3 – x + 3
= 6Incorrect
P(x) = x + 3
And p (x) = x + 3
Then, p(x) + p (x)
= x + 3 – x + 3
= 6 
Question 4 of 10
4. Question
Find the zero of the polynomial p(x) = 5x – 2?
Correct
p(x) = 5x – 2
To find zero of the polynomial, we write
5x – 2 = 0
5x = 2
x = 2/5Incorrect
p(x) = 5x – 2
To find zero of the polynomial, we write
5x – 2 = 0
5x = 2
x = 2/5 
Question 5 of 10
5. Question
Find one of the zeroes of the polynomial 2x^{2} +7x – 4?
Correct
2x^{2} +7x – 4
2x^{2} +8x – x −4
2x(x + 4) – 1(x + 4)
(2x – 1)(x + 4)
2x – 1 = 0 and x + 4 = 0
x = 1/2 and x = 4
Therefore, one zero of the given polynomial is 1/2Incorrect
2x^{2} +7x – 4
2x^{2} +8x – x −4
2x(x + 4) – 1(x + 4)
(2x – 1)(x + 4)
2x – 1 = 0 and x + 4 = 0
x = 1/2 and x = 4
Therefore, one zero of the given polynomial is 1/2 
Question 6 of 10
6. Question
If x^{51}+51 is divided by x+1, then find the remainder?
Correct
x^{51}+51 is divided by x + 1.
It means x = 1 will be one of the value. By putting this value, we can obtain the remainder.
Using remainder theorem,
(−1)^{51 }+ 51
= −1 + 51
= 50
Incorrect
x^{51}+51 is divided by x + 1.
It means x = 1 will be one of the value. By putting this value, we can obtain the remainder.
Using remainder theorem,
(−1)^{51 }+ 51
= −1 + 51
= 50

Question 7 of 10
7. Question
If x+1 is a factor of the polynomial 2x^{2}+kx+1, then find the value of ‘k’?
Correct
If x+1 is a factor of p(x) = 2x^{2}+kx+1,
then by putting x=1, the value of p(x) will be 0.
p(1) = 0
2x^{2}+kx+1= 0
2(−1)^{2}+k(−1)+1= 0
2−k+1= 0
k = 3Incorrect

Question 8 of 10
8. Question
Find the value of 249^{2}−248^{2}?
Correct
(249)^{2 }– (248)^{2}
(249 + 248)(249 – 248) [Using identity a^{2}−b^{2 }= (a + b) (a−b)]
= 497 × 1
= 497
Incorrect
(249)^{2 }– (248)^{2}
(249 + 248)(249 – 248) [Using identity a^{2}−b^{2 }= (a + b) (a−b)]
= 497 × 1
= 497

Question 9 of 10
9. Question
The factorization of 9x^{2}−3x−20 is
Correct
9x^{2}−3x−20
9x^{2}−15x+12x−20
= 3x (3x−5) + 4(3x−5)
= (3x + 4) (3x – 5)
Incorrect
9x^{2}−3x−20
9x^{2}−15x+12x−20
= 3x (3x−5) + 4(3x−5)
= (3x + 4) (3x – 5)

Question 10 of 10
10. Question
If a + b +c = 0, then find a^{3}+b^{3}+c^{3}?
Correct
If a + b + c = 0, then
a^{3}+b^{3}+c^{3}−3abc = (a+b+c)(a^{2}+b^{2}+c^{2}abbcca)
a^{3}+b^{3}+c^{3}−3abc = 0
a^{3}+b^{3}+c^{3} = 3abc
Incorrect
If a + b + c = 0, then
a^{3}+b^{3}+c^{3}−3abc = (a+b+c)(a^{2}+b^{2}+c^{2}abbcca)
a^{3}+b^{3}+c^{3}−3abc = 0
a^{3}+b^{3}+c^{3} = 3abc