Questions :
1.Find the average speed of a bicycle if it completes two round of a circular track of radius 140m twice in 5min 52 sec.
(a) 10m/s
(b) 5m/s
(c) 2m/s
(d) 4m/s
2. If ‘s’ is displacement and ‘d’ is distance between two points, then the correct relation is
(a) s = d
(b) s > d
(c) d > s
(d) none
3. Which of the following figures represents uniform motion of a moving object correctly?
4. A physical quantity which cannot be negative is
(a) displacement
(b) velocity
(c) acceleration
(d) distance
5. A person moves from point O in a straight line to a point X 50m, and return from X to point Y in direction XO 20m. What is displacement made?20. A person moves from point O in a straight line to a point X 50m, and return from X to point Y in direction XO 20m. What is displacement made?
(a) 50m
(b) 80m
(c) 20m
(d) 30m
6. When a body covers unequal distances in equal intervals of time, it is said to be in
(a) linear motion
(b) uniform motion
(c) non-uniform motion
(d) vibratory motion
7. A particle travels with a speed of 18 km/hr, its speed in m/s is
(a) 5 m/s
(b) 50 m/s
(c) 64.8 m/s
(d) 6.48 m/s
8. Which of the following is vector quantity?Which of the following is vector quantity?
(a) Distance
b) Displacement
(c) Velocity
(d) Both (b) and (c)
9. A bus moves from stop ‘A to stop ‘B’ with a speed of 40 km/hr and then from stop ‘B’ to stop ‘A with a speed of 50 km/hr. Its average speed is
(a) 48.5 km/hr
(b) 44 km/hr
(c) 45 km/hr
(d) 44.4 km/hr
10. Area under velocity-time gives
(a) displacement
(b) acceleration
(c) velocity
(d) time
11. Displacement-time graph of a uniformly accelerated motion is
(a) parabola
(b) straight line
(c) an inclined line
(d) none
12. A car with speed 72km/hr suddenly applies break. The break has maximum ability to decelerate with 5ms^(-2). Find time taken to stop the car after applying breaks?A car with speed 72km/hr suddenly applies break. The break has maximum ability to decelerate with 5ms^(-2). Find time taken to stop the car after applying breaks?
(a) 2sec
(b) 3sec
(c) 4sec
(d) 5sec
13. 28. A particle travels 100 metres after starting from rest in 10 seconds. Its acceleration is
(a) 2 m/s2
(b) 4 m/s2
(c) 1 m/s2
(d) 20 m/s2
14. In uniform circular motion, velocity of particle is
(a) constant
(b) variable in magnitude
(c) variable in direction
(d) both (a) and (b)
15. 30. Velocity of a particle increases from 10 m/s to 15 m/s after travelling a distance of 5 metre. Its acceleration is
(a) 12.5 m/s2
(b) 125 m/s2
(c) 1.25 m/s2
(d) 0.125 m/s2
Chapter 8 Motion Quiz 2| Class 9th
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Question 1 of 15
1. Question
Find the average speed of a bicycle if it completes two round of a circular track of radius 140m twice in 5min 52 sec.
Correct
Incorrect
-
Question 2 of 15
2. Question
If ‘s’ is displacement and ‘d’ is distance between two points, then the correct relation is
Correct
Distance is the total measurement of path while displacement is the shortest measurement between two points.
Incorrect
Distance is the total measurement of path while displacement is the shortest measurement between two points.
-
Question 3 of 15
3. Question
Which of the following figures represents uniform motion of a moving object correctly?
Correct
Incorrect
-
Question 4 of 15
4. Question
A physical quantity which cannot be negative is
Correct
Distance can never be negative because it is the measurement of total path length between two points.
Incorrect
Distance can never be negative because it is the measurement of total path length between two points.
-
Question 5 of 15
5. Question
A person moves from point O in a straight line to a point X 50m, and return from X to point Y in direction XO 20m. What is displacement made?
Correct
Incorrect
-
Question 6 of 15
6. Question
When a body covers unequal distances in equal intervals of time, it is said to be in
Correct
Incorrect
-
Question 7 of 15
7. Question
A particle travels with a speed of 18 km/hr, its speed in m/s is
Correct
18 km/hr = 18× (1000/3600) = 18× (5/18) = 5 m/s
Incorrect
18 km/hr = 18× (1000/3600) = 18× (5/18) = 5 m/s
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Question 8 of 15
8. Question
Which of the following is vector quantity?
Correct
Incorrect
-
Question 9 of 15
9. Question
A bus moves from stop ‘A to stop ‘B’ with a speed of 40 km/hr and then from stop ‘B’ to stop ‘A with a speed of 50 km/hr. Its average speed is
Correct
Let the distance between A and B be D and time taken to cover the distance be T1 and T2.
Speed = Distance/Time
40 = (D/T1) and 50 = (D/T2)
T1 = (D/40)
also, T2 = (D/50)
Total time (T) = T1 + T2
⇒ (D/40) + (D/50) = (9D/200)
Total Distance = (D + D) = 2D
Average speed = Total Distance/Total Time Taken
= (2D/(9D/200)) = 400/9 = 44.4 km/hr
Incorrect
Let the distance between A and B be D and time taken to cover the distance be T1 and T2.
Speed = Distance/Time
40 = (D/T1) and 50 = (D/T2)
T1 = (D/40)
also, T2 = (D/50)
Total time (T) = T1 + T2
⇒ (D/40) + (D/50) = (9D/200)
Total Distance = (D + D) = 2D
Average speed = Total Distance/Total Time Taken
= (2D/(9D/200)) = 400/9 = 44.4 km/hr
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Question 10 of 15
10. Question
Area under velocity-time gives
Correct
Velocity is on Y-axis. Time is on X-axis. The area of the graph will be Y-axis × X-axis.
Therefore, Area = Velocity × Time = m/s × s = m = displacement
Incorrect
Velocity is on Y-axis. Time is on X-axis. The area of the graph will be Y-axis × X-axis.
Therefore, Area = Velocity × Time = m/s × s = m = displacement
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Question 11 of 15
11. Question
Displacement-time graph of a uniformly accelerated motion is
Correct
Incorrect
-
Question 12 of 15
12. Question
A car with speed 72km/hr suddenly applies break. The break has maximum ability to decelerate with. Find time taken to stop the car after applying breaks?
Correct
Incorrect
-
Question 13 of 15
13. Question
A particle travels 100 metres after starting from rest in 10 seconds. Its acceleration is
Correct
s = 100 m, u = 0, t = 10 s
Using, s = ut + ½ at2
100 = 0 + ½ a (10)2
⇒ 200 = 100 a
⇒ a = 2 m/s2
Incorrect
s = 100 m, u = 0, t = 10 s
Using, s = ut + ½ at2
100 = 0 + ½ a (10)2
⇒ 200 = 100 a
⇒ a = 2 m/s2
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Question 14 of 15
14. Question
In uniform circular motion, velocity of particle is
Correct
Velocity depends on direction and in uniform circular motion direction changes always.
Incorrect
Velocity depends on direction and in uniform circular motion direction changes always.
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Question 15 of 15
15. Question
Velocity of a particle increases from 10 m/s to 15 m/s after travelling a distance of 5 metre. Its acceleration is
Correct
u = 10 m/s, v = 15 m/s and s = 5 m
v2 = u2 + 2as
⇒ 152 = 102 + (2×a×5)
⇒ 225 = 100 + 10a ⇒ 10 a = 125 ⇒ a = 12.5 m/s2
Incorrect
u = 10 m/s, v = 15 m/s and s = 5 m
v2 = u2 + 2as
⇒ 152 = 102 + (2×a×5)
⇒ 225 = 100 + 10a ⇒ 10 a = 125 ⇒ a = 12.5 m/s2